I am busy changing the world

It's just simple as this function: function my_get_posts( $query ) {     if ( is_home() && false == $query->query_vars['suppress_filters'] )                 $query->set('orderby', 'menu_order');                 $query->set('order', 'ASC');      return $query; } Basically, you need to order the posts by menu_order attribute.

To display last published posts from the entire network on the main blog of your WordPress Multisite, you can use this plugin I wrote (*) yesterday: Github repo:   https://github.com/dangtrinh/WordPress_Multisites_Utilities_Plugin 1. Install the WordPress Multisite Utilities Plugin: $ cd /var/www/your_wordpress_installation/wp-content/plugins $ git clone https://github.com/dangtrinh/WordPress_Multisites_Utilities_Plugin 2. Activate the plugin for your network (network only) 3. In your home page template file (for example page-home.php), call the  get_recent_network_posts function to get latest posts (6 posts by default) from your network. For example: <?php $lastposts = get_recent_network_posts(); foreach( $lastposts as $post): ?> <div class="col-1-3"> <div class="blog-post"> <div class="blog-post-thumbnail" style="background-image: url('<?php echo $post['thumb_url'];?>')"...

If you post form data using cURL in php, you cannot use the ' @ ' character at the beginning of a data string value (e.g: password=@@mypassword ). ' @ ' is the indicator for file path in POST operation of cURL. You need to disable the '@' prefix to be able to send data string start with '@' character. Here is the description of PHP cURL's CURLOPT_POSTFIELDS option: CURLOPT_POSTFIELDS The full data to post in a HTTP "POST" operation. To post a file, prepend a filename with @ and use the full path. The filetype can be explicitly specified by following the filename with the type in the format ';type=mimetype'. This parameter can either be passed as a urlencoded string like 'para1=val1&para2=val2&...' or as an array with the field name as key and field data as value. If value is an array, the Content-Type header will be set to multipart/form-data. As of PHP 5.2.0, value must be an array if files are passed to...

I've just found a shorter way to work with Django form in a view with POST request. Instead of: def home (request): if request.method == 'POST': myform = MyForm(request.POST, request.FILES) if myform.is_valid(): myform.save() return redirect('home') else: myform = MyForm() return render_to_response('home.html', locals(), context_instance=RequestContext(request)) I can do something like this: def home (request): myform = MyForm(request.POST or None) if myform.is_valid(): myform.save() return redirect('home') return render_to_response('home.html', locals(), context_instance=RequestContext(request))

When a form is submitted, I wanna get the value of a key (variable) which is in the POST/GET data. For example: myvalue = request.POST['mykey'] But if for some reason, the POST/GET data does not contains that data ('mykey': 'myvalue'). In this case, I have to check if the key 'mykey' is sent in POST/GET data and check if that key is not empty: if 'mykey' in request.POST.keys() and request.POST['mykey']:       myvalue = request.POST['mykey'] There is a Python method available on any Python dictionary names  get() . get() lets you ask for the value of a particular key and specify a default to fallback on if the key doesn't exist. And, POST and GET are dictionaries. myvalue = request.POST.get('mykey', '') That get() method will save me (and you) so much time!